Answer:
the average induced emf in the coil is 0.016 V.
Step-by-step explanation:
Given;
diameter of the wire, d = 14.1 cm = 0.141 m
change in magnetic filed strength, dB = 0.52 T - 0.23 T = 0.29 T
change in time, dt = 0.28 s
The area of the wire is calculated as follows;
![A = (\pi d^2)/(4) \\\\A = (\pi * (0.141)^2)/(4) \\\\A = 0.0156 \ m ^2](https://img.qammunity.org/2022/formulas/physics/college/2g13xhitzx6y28paiziz05bzpw3lah3hs7.png)
The induced emf is calculated as follows;
![emf = (dBA)/(dt) \\\\emf = (0.29 * 0.0156)/(0.28) \\\\emf = 0.016 \ V](https://img.qammunity.org/2022/formulas/physics/college/uelf7bkovq64aa53u8n9guywnhr0sh4eww.png)
Therefore, the average induced emf in the coil is 0.016 V.