Question

Find the length of a rectangle with a perimeter of 148 inches and width of 36 inches.
inches

Answer 1

Perimeter of rectangle = 2L + 2W

2L + 2 * 36 = 148

2L = 148 - 72

2L = 76

L = 38 inches

Answer 2

Given :-

• Width of rectangle = 36 inches
• Perimeter of rectangle = 148 inches.

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To find:-

• Length of rectangle

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Solution:-

We know:-

`\bigstar \boxed{ \rm Perimeter \: of \: rectangle = 2(length + width)}`

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So:-

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`\dashrightarrow \sf 148 = 2(length + 36) \\`

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`\dashrightarrow \sf 148 = 2(length) + 2(36) \\`

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`\dashrightarrow \sf 148 = 2(length) + 2 * 36 \\`

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`\dashrightarrow \sf 148 = 2(length) + 72 \\`

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`\dashrightarrow \sf 148 = 2length + 72 \\`

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`\dashrightarrow \sf 148 - 72= 2length \\`

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`\dashrightarrow \sf76= 2length \\`

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`\dashrightarrow \sf 2length = 76 \\`

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`\dashrightarrow \sf length = (76)/(2) \\`

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`\dashrightarrow \sf length = \cancel (76)/(2) \\`

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`\dashrightarrow \bf length = 38 \: inches`