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21 votes
Find the length of a rectangle with a perimeter of 148 inches and width of 36 inches.
inches

User Crankparty
by
4.0k points

2 Answers

8 votes

Answer:

Perimeter of rectangle = 2L + 2W

2L + 2 * 36 = 148

2L = 148 - 72

2L = 76

L = 38 inches

User DavidK
by
3.2k points
9 votes

Given :-

  • Width of rectangle = 36 inches
  • Perimeter of rectangle = 148 inches.


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To find:-

  • Length of rectangle


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Solution:-

We know:-


\bigstar \boxed{ \rm Perimeter \: of \: rectangle = 2(length + width)}


\\

So:-


\\


\dashrightarrow \sf 148 = 2(length + 36) \\


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\dashrightarrow \sf 148 = 2(length) + 2(36) \\


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\dashrightarrow \sf 148 = 2(length) + 2 * 36 \\


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\dashrightarrow \sf 148 = 2(length) + 72 \\


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\dashrightarrow \sf 148 = 2length + 72 \\


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\dashrightarrow \sf 148 - 72= 2length \\


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\dashrightarrow \sf76= 2length \\


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\dashrightarrow \sf 2length = 76 \\


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\dashrightarrow \sf length = (76)/(2) \\


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\dashrightarrow \sf length = \cancel (76)/(2) \\


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\dashrightarrow \bf length = 38 \: inches

User Tony Hensler
by
2.6k points