Question

Please help asap tysm 3

Answer 1

Given :

• Area of rhombus = 0.15 feet²
• First Diagonal of rhombus = 0.5 feet

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To find:

• Second Diagonal of rhombus

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Solution:

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We know:-

`\bigstar \boxed{ \rm Area \: of \: rhombus = (Diagonal_1 * Diagonal_2)/(2) }`

By using this formula we can find second Diagonal as area of first Diagonal already given.

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So:-

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`\leadsto\sf 0.15 = (0.5 * Diagonal_2)/(2)`

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`\leadsto\sf 0.15 = (5 * Diagonal_2)/(2 * 10)`

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`\leadsto\sf 0.15 = \frac{\cancel5 * Diagonal_2}{2 * \cancel{10}}`

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`\leadsto\sf 0.15 = ( Diagonal_2)/(2 * 2)`

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`\leadsto\sf 0.15 = ( Diagonal_2)/(4)`

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`\leadsto\sf ( Diagonal_2)/(4) = 0.15`

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`\leadsto\sf Diagonal_2 = 0.15 * 4`

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`\leadsto\sf Diagonal_2 = (15)/(100) * 4`

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`\leadsto\sf Diagonal_2 = \frac{15}{\cancel{100}} *\cancel 4`

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`\leadsto\sf Diagonal_2 = (15)/(25) *1`

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`\leadsto\sf Diagonal_2 = (15)/(25)`

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`\leadsto\sf Diagonal_2 = (3)/(5)`

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`\leadsto\bf Diagonal_2 = 0.6 \: feet`

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`\therefore\underline{ \textsf{ \textbf{Diagonal$_2$ of rhombus \: = \red{0.6 feet}}}}`