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Please help asap tysm 3

asked Nov 17, 2023 100k views

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War · Answer 1 · 2023-11-23T17:36:09+0000

Given :

Area of rhombus = 0.15 feet²
First Diagonal of rhombus = 0.5 feet

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To find:

Second Diagonal of rhombus

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Solution:

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We know:-

$\bigstar \boxed{ \rm Area \: of \: rhombus = (Diagonal_1 * Diagonal_2)/(2) }$

By using this formula we can find second Diagonal as area of first Diagonal already given.

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So:-

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$\leadsto\sf 0.15 = (0.5 * Diagonal_2)/(2)$

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$\leadsto\sf 0.15 = (5 * Diagonal_2)/(2 * 10)$

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$\leadsto\sf 0.15 = \frac{\cancel5 * Diagonal_2}{2 * \cancel{10}}$

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$\leadsto\sf 0.15 = ( Diagonal_2)/(2 * 2)$

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$\leadsto\sf 0.15 = ( Diagonal_2)/(4)$

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$\leadsto\sf ( Diagonal_2)/(4) = 0.15$

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$\leadsto\sf Diagonal_2 = 0.15 * 4$

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$\leadsto\sf Diagonal_2 = (15)/(100) * 4$

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$\leadsto\sf Diagonal_2 = \frac{15}{\cancel{100}} *\cancel 4$

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$\leadsto\sf Diagonal_2 = (15)/(25) *1$

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$\leadsto\sf Diagonal_2 = (15)/(25)$

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$\leadsto\sf Diagonal_2 = (3)/(5)$

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$\leadsto\bf Diagonal_2 = 0.6 \: feet$

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$\therefore\underline{ \textsf{ \textbf{Diagonal$_2$ of rhombus \: = \red{0.6 feet}}}}$

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Given :

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Solution:

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