Question

Whats the answer for y=-
`(2)/(3)`x+4 and y=
`(1)/(3)`x-2

Answer 1

Explanation:

`y = -(2)/(3)x + 4`

`y = (1)/(3)x - 2`

Since both equations are set equal to
`y`, we can take the right-hand side of each equation and set them equal to each other to solve for
`x`:

`-(2)/(3)x + 4 = (1)/(3)x - 2`

`-(2)/(3)x - (1)/(3)x = -2 - 4`

`-x = -6`

`x = 6`

Now we can plug this value into either equation to solve for
`y`:

`y = (1)/(3)x - 2`

`y = (1)/(3)(6) - 2`

`y = 2 - 2`

`y = 0`

So the solution to the system of equations is
`(6, 0)`