Explanation:
To be honest for this question you DO NOT have to use pythagoras theorem , and you can't either as you won't be able to start.
I have a method called the TOA CAH SOH method, which comprises 3 formulas,
TOA (tangent = opposite/adjacent)
CAH (cosine = adjacent/hypotenuse)
SOH (sine = opposite/hypotenuse)
In this case we will solve the question in alphabetical order starting with x.
for x, we can use TOA.

Since now we know x, we can then use pythogoras theorem to find y.
By pythagoras theorem,

Finding Z is easy. We know that this is a triangle, which means
