Complete question :
a triangular land having area 36m²and perimeter 84 m has length of the edge 26m. Calculate the measure of remaining two sides
Answer:
28cm, 30 cm
Explanation:
Area = 336 m³ ; lebgth of edge = 26
Perineter, p = 84
Perimeter of triangle :
a + b + c
Length of other two sides = 84 - 26 = 58
If length of one of the sides = x
Lenvyb if the other = 58 - x
From Hero's formular :
Sqrt(s(s-a)(s-b)(s-c).
s = perimeter /2 = 84/2 = 42
Sqrt(42(42 - 26)(42 - x)(42 - (58-x))
sqrt(42(16)(42-x)(42-58+x) = 336
sqrt(42(16)(42-x)(-16+x) = 336
672(42-x)(x - 16) = 112896
(42 - x)(x - 16) = 168
42x - 672 - x² + 16x = 168
-x² + 58x - 840 = 0
Using the quadratic equation solver, the roots are :
28, 30
Hence.the other tow sides are 28 cm and 30 cm