Answer:
I = 1.23 A
Step-by-step explanation:
Given that,
The resistance of the lightbulb, R = 96.8 Ω
Voltage, V = 120 V
We need to find the current flows through the lightbulb. Let the current be I. We can use the ohm's law to find it i.e.
![V=IR\\\\I=(V)/(R)\\\\I=(120)/(96.8)\\\\I=1.23\ A](https://img.qammunity.org/2022/formulas/chemistry/high-school/ciu47men7wlvj397uybkd4n63mao2177hw.png)
So, the current flows through the bulb is 1.23 A.