Answer:
the temperature of the intermediate reservoir is 624.5 K
Step-by-step explanation:
Given the data in the question
The two Carnot heat engines are operating in series;
[ T
]
↓
((1)) ⇒ W
↓
[ T
]
↓
((2)) ⇒ W
[ T
]
The maximum possible efficiency for any heat engine is the Carnot efficiency;
η
= 1 -
the thermal efficiencies if both engines are the same will be;
η
= η
1 -
= 1 -
1 - 1 -
= -
-
= -
=
T
² = T
× T
T
= √(T
× T
)
source temperature of the first engine T
= 1300 K
sink temperature of the second engine T
= 300 K
we substitute
T
= √(300 × 1300)
T
= √390000
T
= 624.4998 K ≈ 624.5 K
Therefore, the temperature of the intermediate reservoir is 624.5 K