1 Answer

Juto · Answer 1 · 2022-10-11T18:59:45+0000

Answer:

p =(1)/(6)

Explanation:

Given

$Polygons =\{Quadrilateral, Pentagon, Hexagon, Octagon, Nonagon, Decagon\}$

Required

Probability of assigning a nonagon

From the given set of polygons, there are 6 polygons in the set and 1 one of them is a nonagon

This means that:

n = 6 --- Total

Nonagons = 1

So, the probability, p is:

p =(Nonagons)/(n)

p =(1)/(6)

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