Given:
The points are A(3, -3), B(-3, -2), C(-5, 1), D(-5, 4), E(-4 ,6), F(-2, 6), G(3, 2).
To find:
The length of EF and plot each point on a coordinate plane and connect them.
Solution:
Plot the given point A(3, -3), B(-3, -2), C(-5, 1), D(-5, 4), E(-4 ,6), F(-2, 6), G(3, 2) on coordinate plane and connect them as shown in the below figure.
From the below graph it is clear that the length of EF is 2 units. We can verify this solution by using the distance formula.
Distance formula:
![D=√((x_2-x_1)^2+(y_2-y_1)^2)](https://img.qammunity.org/2022/formulas/mathematics/college/7dbso8bdyt19yzvt4l4ycqaby0aaqlyhbo.png)
Using the distance formula, the distance between E(-4 ,6) and F(-2, 6) is
![D=√((-2-(-4))^2+(6-6)^2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/6ttqw5ngdaw47n957z1pxcnawqjhqc1pkz.png)
![D=√((-2+4)^2+(0)^2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/s20tzqgptneqg9uj59vtlyh3qxlzi1krxp.png)
![D=√((2)^2+0)](https://img.qammunity.org/2022/formulas/mathematics/high-school/7vhyfwgmovsreyhy1d2or0u8vd2ru32rea.png)
![D=2](https://img.qammunity.org/2022/formulas/mathematics/high-school/fbvrrj4ak5ck1bps8f1dmz47nu83mhg3i3.png)
Therefore, the length of EF is 2 units.