Question

Consider the probability that at least 93 out of 154 CDs will not be defective. Assume the probability that a given CD will not be defective is 61%.

Approximate the probability using the normal distribution. Round your answer to four decimal places.

Answer 1

0.5962

Explanation:

Given that :

p = 61% = 0.61

q = 1 - p = 1 - 0.61 = 0.39

n = 154 ; x = 93

Using the binomial probability formula :

P(x =x) = nCx * p^x * (1 - p)^(n - x)

P(x>=93) = p(x=93)+p(x=94)+...+p(x=n)

P(x>= 93) = 0.59619

P(x>= 93) = 0.5962