Question

I need a solution on how to do this!!!!
simplify fully

Answer 1

`(x-5)/(x-7)` is the answer

Explanation:

`(x^(2)-2x -15 )/( x^(2)-4x-21)`

Factorising,

`(x^(2)-5x+3x-15)/(x^(2)-7x+3x-21 )`

`(x(x-5)+3(x-5))/(x(x-7)+3(x-7))`

`((x+3)(x-5))/((x+3)(x-7))`

`(x-5)/(x-7)`

Answer 2

`(x-5)/(x-7)`

Explanation:

Given

`(x^2-2x-15)/(x^2-4x-21)` ← factor numerator and denominator

=
`((x-5)(x+3))/((x-7)(x+3))` ← cancel (x + 3) on numerator and denominator

=
`(x-5)/(x-7)`