Answer:
EF = 13 units
Explanation:
Points E and F are the ends of segment EF.
Coordinates of E → (-7, -5)
Coordinates of F → (-2, 7)
Since, length of a segment joining points
and
is given by,
Length of segment =
![√((x_1-x_2)^2+(y_1-y_2)^2)](https://img.qammunity.org/2022/formulas/mathematics/college/wzykgycjx8b7mgp7t4o6td9xur5zcmp9qj.png)
Length of segment EF =
![√((-7+2)^2+(-5-7)^2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/x7fj6hqq2phn9gwihloiu56yqvywtgbi4a.png)
=
![√((-5)^2+(-12)^2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/52h2uolu7q020hj4eph0sfc6tb4tvf9lll.png)
=
![√(169)](https://img.qammunity.org/2022/formulas/mathematics/high-school/m94x4lh0uzeags1xrbgqxwyzlfnlbxyhje.png)
= 13
Therefore, length of segment EF is 13 units.