Answer:
1. The ratio of their diameters is 8/5 = 8 : 5
2. The ratio of their surface area is (8/5)²
3. The ratio of their volume is (8/5)³
4.The area of the base of the larger cylinder is 128 cm²
Explanation:
Given that the two cylinders are similar, we have;
Two cylinders are similar when the ratio of their heights is equal to the ratio of their radii
Therefore, we have;
1. The ratio of the height of the two cylinders = 8/5 = The radio of their radii = r₁/r₂
The ratio of their diameter = D₁/D₂ = 2·r₁/2·r₂ = r₁/r₂ = 8/5
The ratio of their diameters D₁/D₂ = 8/5 = 8 : 5
2. The surface area of the cylinders = 2·π·r·h + 2·π·r²
Therefore, we have;
(2·π·r₁·h₁ + 2·π·r₁²)/(2·π·r₂·h₂ + 2·π·r₂²) = (r₁·h₁ + r₁²)/(r₂·h₂ + r₂²)
h₁ = h₂ × 8/5
r₁ = r₂ × 8/5
= (8/5)²(r₂·h₂ + r₂²)/(r₂·h₂ + r₂²) = (8/5)²
The ratio of their surface area = (8/5)²
3. The volume of the cylinder = π·r²·h
∴ The ratio of the volume = (π·r₁²·h₁)/(π·r₂²·h₂) = (8/5)³ × (π·r₂²·h₂)/(π·r₂²·h₂) = (8/5)³
The ratio of their volume = (8/5)³
4. The ratio of the area of the base of the larger cylinder to the area of the base of the smaller cylinder is (8/5)²
Therefore if the area of the base of the smaller cylinder is 50 cm², the area of the base of the larger cylinder = 50 cm² × (8/5)² = 128 cm²