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What are the roots of the equation 2x2 - 6x + 3 = 0?

What are the roots of the equation 2x2 - 6x + 3 = 0?-example-1
User Ojk
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2 Answers

5 votes

Answer:

Explanation:

What are the roots of the equation 2x2 - 6x + 3 = 0?-example-1
User Pawel Kiszka
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5 votes

Answer:

Explanation:

The given possible roots have the form that we'd get by using the quadratic formula, so let's start with that. Here the coefficients are {2, -6, 3}, and so the discriminant (b^2 - 4ac) is (-6)^2 - 4(2)(3), or 36 - 24 = 12.

Because the discriminant is positive we know immediately that there are two different real roots.

-(-6) ± √12 6 ± √12

x = ------------------ = ---------------- These are equivalent to Answers E and F.

2(2) 4

User Mercury Platinum
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