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4 votes
A hemispherical tank is filled with water and has a diameter of 22 feet. If water

weighs 62.4 pounds per cubic foot, what is the total weight of the water in a full tank,
to the nearest pound?

User Harkish
by
4.5k points

2 Answers

2 votes

Answer:

just do the exam

Explanation:

User Vladimir Korenev
by
5.0k points
3 votes

Answer:

173,949 lb

Explanation:

Volume of a sphere:


V_(sphere) = (4)/(3)\pi r^3

A hemisphere is half of a sphere, so its volume is half of the volume of a sphere with the same diameter. Also, radius = diameter/2.


V_(hemisphere) = (2)/(3)\pi ((d)/(2))^3


V_(hemisphere) = (2)/(3) * 3.14159 * ((22~ft)/(2))^3


V_(hemisphere) = 2787.639~ft^3

Now we use the density of water to find the weight of the water contained in the tank.

weight = volume * density

weight = 2787.639 ft^3 * 62.4 lb/ft^3

weight = 173,949 lb

User Cliabhach
by
5.1k points