Force {x }^(2) + 6x + 8 ​

Question

Force

`{x }^(2) + 6x + 8`
​

Answer 1

x=-2,-4 is your answer

x²+6x+8=0

doing middle term factorization

x²+4x+2x+8=0

x(x+4)+2(x+4)=0

(x+4)(x+2)=0

either

x=-4

or

x=-2

Answer 2

Explanation:

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`\underline{ \underline{ \large{\tt{T \: O \: \: F \: A \: C \: T \: O \: R \: I\: Z \: E \: }}}} :`

• 
  `\large{ \tt{ {x}^(2) + 6x + 8}}`

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`\underline{ \underline{ \large { \tt{S \: O \: L \: U \: T \: I \: O \: N}} }} :`

Firstly find two numbers which when multiplied results to 8 and when added,it results to 6. The two numbers must be 4 and 2.

⟶
`\large{ \tt{ {x}^(2) + (4 + 2)x + 8}}`

⟶
`\large{ \tt{ \underbrace{{x}^(2) + 4x} + \underbrace{2x + 8}}}`

Now, Take common from first two terms :

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`\large {\tt{x(x + 4) + 2x + 8}}`

Take common from last two terms :

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`\large{ \tt{x(x + 4) + 2(x + 4)}}`

⟶
`\large{ \tt{(x + 4)(x + 2)}}`

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`\boxed{ \boxed{ \underline{ \text{Our \: Final \: Answer : \boxed{ \bold{ \text{(x + 4)(x + 2)}}}}}}}`

Hope I helped ! ツ

Have a wonderful day / night ! ♡

✧
`\underline{ \underline{ \mathfrak{Carry \: on \: learning}}}` !! ✎

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