Question

a four digit number is divided by 25 and has a remainder of 18. the first 3 digits of the number are 329. what is the fourth digit of the number?

Answer 1

As per the Question :

25=
x
25
=
Remainder =8
=
8

26=
x
26
=
Remainder =0
=
0

So,

=25+8
x
=
25
a
+
8

=26+0
x
=
26
b
+
0

Since, there are two equations and three variables :

=
a
=
b
or the divisors will have to be equal to make this question valid

Therefore,

=25+8−()
x
=
25
a
+
8
−
(
i
)

=26+0−()
x
=
26
a
+
0
−
(
i
i
)

Subtracting (),()
(
i
)
,
(
i
i
)

−=25−26+8−0
x
−
x
=
25
a
−
26
a
+
8
−
0

=0=−+8
=
0
=
−
a
+
8

=−=−8
=
−
a
=
−
8
or =8
a
=
8

Therefore,

=25×8+8
x
=
25
×
8
+
8

=208
x
=
208

=26×8+0
x
=
26
×
8
+
0

=208
x
=
208

Good Luck, Champ!
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Answer 2

are you sure that the remainder is 18 and not 8