Question

Consider the redox reaction below. Upper M g (s) plus Pper f e superscript 2 plus (a q) right arrow upper M g superscript 2 plus (a q) plus upper F e (s). Which equation is a half reaction that describes the reduction that is taking place?

Answer 1

A

Step-by-step explanation:

edge

Answer 2

Answer:
`Fe^(2+)(aq)+2e^-\rightarrow Fe(s)`

Step-by-step explanation:

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

`Mg(s)+Fe^(2+)(aq)\rightarrow Fe(s)+Mg^(2+)(aq)`

The oxidation half reaction is:

`Mg(s)\rightarrow Mg^(2+)(aq)+2e^-`

The reduction half reaction is:

`Fe^(2+)(aq)+2e^-\rightarrow Fe(s)`