Answer:
The vertex is ( -6, 3)
Explanation:
h(x) = |x+ 6| + 3
Inside the absolute value is the h or the x coordinate of the vertex
Outside is the k or the y value of the vertex
It is in the form
h(x) = |x-h| + k where (h,k) is the vertex
h(x) = |x - -6| + 3
The vertex is ( -6, 3)