Question

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Calculate the amount of torque of an object being pushed by 6 N force along a circular path of a radius of 1x10^-2 mat 30 degree angle

Answer 1

`\tau=0.03\ N-m`

Step-by-step explanation:

Given that,

Force acting, F = 6N

The radius of the path,
`r=10^(-2)\ m`

Angle,
`\theta=30^(\circ)`

We need to find the amount of torque acting on the object. The formula for torque is given by :

`\tau=Fr\sin\theta\\\\\tau=6* 10^(-2)* \sin(30)\\\\\tau=0.03\ N-m`

So, the required torque is equal to 0.03 N-m.