Question

Find the equation of the circle that passes through the points (0,0), (2,0)&(3,-3)​

Answer 1

Explanation:

A(0,0), B(2,0), C(3,-3)

Perpendicular bisector of AB: x=1

Perpendicular bisector of AC: y=x-3

Center of circle = intersection of perpendicular bisectors = (1,-2)

Radius = √5

(x-1)² + (y+2)² = 5