Find the equation of the circle that passes through the points (0,0), (2,0)&(3,-3)

Question

asked Feb 25, 2022 126k views

1 Answer

Dzhefer · Answer 1 · 2022-03-02T03:46:29+0000

Answer:

Explanation:

A(0,0), B(2,0), C(3,-3)

Perpendicular bisector of AB: x=1

Perpendicular bisector of AC: y=x-3

Center of circle = intersection of perpendicular bisectors = (1,-2)

Radius = √5

(x-1)² + (y+2)² = 5