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5 votes
Solve for x
2^x= 0.0625(X is an integer)

User Mkso
by
4.7k points

2 Answers

3 votes
Answer=x=-4

This question is to do with logs and indices

2^x =0.0625

we know that 2³=8
And log2(8) = 3

*using this form we can solve for x*

2³=8
2^x =0.0625

log?(?) = ?

Both indices have a base of 2 so the log2 stays the same

Instead of 8 we put the 0.0625 in the bracket

So we get
log2(0.0625) = ?
Put this in your calculator and you should get

log2(0.0625) = -4
User ThW
by
3.9k points
2 votes

Answer:

there you go:)

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Solve for x 2^x= 0.0625(X is an integer)-example-1
User Nishchit
by
3.8k points