Question

Solve the system using elimination. 4y+x= -17 -2y+2x =16

Answer 1

Explanation:

Let's solve your system by elimination.

4y+x=−17;−2y+2x=16

Multiply the first equation by -2,and multiply the second equation by 1.

−2(4y+x=−17)

1(−2y+2x=16)

Becomes:

−2x−8y=34

2x−2y=16

Add these equations to eliminate x:

−10y=50

Then solve −10y= 50 for y:

−10y=50

−10y /−10 = 50/ −10 (Divide both sides by -10)

y = −5

Now that we've found y let's plug it back in to solve for x.

Write down an original equation:

4y + x = −17

Substitute −5 for y in 4y+x=−17:

(4)(−5)+x=−17

x−20=−17(Simplify both sides of the equation)

x−20+20=−17+20(Add 20 to both sides)

x=3

Answer:

x=3 and y=−5

HOPE IT WILL HELP :)

Answer 2

(3, -5)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Distributive Property

Equality Properties

• Multiplication Property of Equality
• Division Property of Equality
• Addition Property of Equality
• Subtraction Property of Equality

Algebra I

• Coordinates (x, y)
• Solving systems of equations using substitution/elimination

Explanation:

Step 1: Define Systems

4y + x = -17

-2y + 2x = 16

Step 2: Rewrite Systems

-2y + 2x = 16

1. [Multiplication Property of Equality] Multiply 2 to both sides: 2(-2y + 2x) = 32
2. [Distributive Property] Distribute 2: -4y + 4x = 32

Step 3: Redefine Systems

4y + x = -17

-4y + 4x = 32

Step 4: Solve for x

Elimination

1. Combine equations: 5x = 15
2. [Division Property of Equality] Divide 5 on both sides: x = 3

Step 5: Solve for y

1. Substitute in x [Original Equation]: 4y + 3 = -17
2. [Subtraction Property of Equality] Subtract 3 on both sides: 4y = -20
3. [Division Property of Equality] Divide 4 on both sides: y = -5