Question

How many mL of isopropyl alcohol solution (40% v/v) would contain 2.5 mL of isopropyl alcohol? Report your answer in mL

Answer 1

`V_(solution)=6.25mL`

Step-by-step explanation:

Hello there!

In this case, given the by-volume percent and the volume of isopropyl alcohol as the solute, we can compute the volume of the solution via:

`\% v/v=(V_(solute))/(V_(solution)) *100\%\\\\V_(solution)=(V_(solute))/(\% v/v) *100\%`

Now, we plug in the given data to obtain:

`V_(solution)=(2.5mL)/(40\%) *100\%\\\\V_(solution)=6.25mL`

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