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The average life expectancy of people in the united states in 2018 was 78.54 years with a standard deviation of approximately 15 years

User Tiya
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Question:

The average life expectancy of people in the United States in 2018 was 78.54 years with a standard deviation of approximately 15 years.

Suppose we take a sample of 40 individuals in the United States, what are the mean and standard deviation for sample averages from samples of size 40?

Answer:


\bar x = 78.54


\sigma_x = 2.37

Explanation:

Given


\mu = 78.54 --- Population mean


\sigma = 15 --- Population standard deviation


n = 40 --- Sample size

Solving (a): The sample mean

According to the central limit theorem, sample mean is always equal to the population mean.

So:


\bar x = 78.54

Solving (b): The sample standard deviation

Using the central limit theorem, we have:


\sigma_x = (\sigma)/(\sqrt n)

So:


\sigma_x = (15)/(√(40))


\sigma_x = (15)/(6.32)


\sigma_x = 2.37

User Jiselle
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