Question

A gas occupies 5.31 liters at a pressure of 0.55 atm. Determine the volume at standard pressure.

A. 2.92
B. 8.28L
C. 3.54 L
D. 9.65L

Answer 1

Option A; V = 2.92 L

Step-by-step explanation:

If we assume a lot of things, like:

The gas is an ideal gas.

The temperature is constant.

The gas does not interchange mass with the environment.

Then we have the relation:

P*V = n*R*T = constant.

Where:

P = pressure

V = volume

n = number of moles

R = constant of the ideal gas

T = temperature.

We know that when P = 0.55 atm, the volume is 5.31 L

Then:

(0.55 atm)*(5.31 L) = constant

Now, when the gas is at standard pressure ( P = 1 atm)

We still have the relation:

P*V = constant = (0.55 atm)*(5.31 L)

(1 atm)*V = (0.55 atm)*(5.31 L)

Now we only need to solve this for V.

V = (0.55 atm/ 1 atm)*(5.31 L) = 2.92 L

V = 2.92 L

Then the correct option is A.