Question

Factor by grouping
3n^3 - 12n^2 + 2n - 8
(show the work pls..)

Answer 1

The answer will be ( n - 4 ) ( 3n² + 2 ).

Explanation:

1) Factor out common terms in the first two terms, then in the last two terms.

`{3n}^(2) (n - 4) + 2(n - 4)`

2) Factor out the common term n - 4.

`(n - 4)( {3n}^(2) + 2)`

Therefor, the answer is ( n - 4 ) ( 3n² + 2 ).