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See image for question.

Please show workings and diagrams.​

See image for question. Please show workings and diagrams.​-example-1

1 Answer

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Answer:

  • a) 16.4 m, 101°
  • b) 6.22 m, 51 m²

Explanation:

Find the measure of angle Q:

  • 50° + (180° - 130°) = 100°

a) Find PR using the law of cosines:

  • PR = √(8² + 13² - 28*13*cos 100°) = 16.4 m (rounded)

Find ∠P using law of sines:

  • 16.4/sin 100° = 13/ sin P
  • m∠P = arcsin (13 sin 100° / 16.4) = 51° (rounded)

The bearing of R from P is:

  • 50° + 51° = 101°

b)

Find the measure of h, the distance from Q to PR:

  • h/ PQ = sin P
  • h = PQ sin P
  • h = 8 sin 51° = 6.22 m

Find the area of ΔPQR:

  • A = 1/2PR*h
  • A = 1/2(16.4)(6.22) = 51 m²
See image for question. Please show workings and diagrams.​-example-1
User Rupert Angermeier
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