Answer:
hello some part of your question is missing below is the missing part
If Dayton's machine is being used on a trial basis, should its purchase be considered? C.V.(S) = Test Statistic= P-Value= Decision: Conclusion:
answer :
i ) Cv(s) = 51.739
ii) T = 44.8
iii) p-value = 0.0082
iv) we do not fail to reject H0 ( since p-value < 0.05 )
v ) The new machine fills the bottles with a lesser variation
Explanation:
we will test the hypothesis in regards to the standard deviation of the population
The hypothesis are
H0 : б = 0.15
Ha : б < 0.15
hence at ∝ = 0.05 where n = 71
i) critical point for left sided test =
hence Cv(s) = 51.739
ii) Test statistic = T = ( n - 1 ) s^2 / б^2
s = 0.12 , n = 71 , б = 0.15
hence T = 44.8
iii) P-value = p (
< 44.8 ) = 0.0082
iv ) Decision : we do not fail to reject H0 ( since p-value < 0.05 )
v ) conclusion : The new machine fills the bottles with a lesser variation