Question

You are crouched at the "start" line. Bang! The race begins and 7 seconds later you end up 60 yards down the track. What was your "acceleration?"

Answer 1

a = 7.35 ft / s²

Step-by-step explanation:

For this exercise we must use the kinematics relations

x = v₀ t + ½ a t²

as the runner leaves the starting line his initial velocity is zero

x = ½ a t²

a =
`(2x)/(t^2)`

let's reduce the distance to foot

x = 60 yd (3ft / 1yd) = 180 ft

let's calculate

a = 2 180 / 7²

a = 7.35 ft / s²