Question

A skyrocket is launched from a 30–foot-high platform, with initial speed 300 ft/s. If the polynomial −16t2 + 300t + 30 gives the height that the rocket will rise in t seconds, how high will a rocket with a 2–second fuse rise? The rocket will rise feet.

Answer 1

566 ft

Explanation:

Given the polynomial equation

-16t² + 300t + 30 = 0

We're asked to find how high the rocket would rise in a 2 second fuse rise. This is a simple instruction that can be obtained by setting the unknown, t, in the equation to 2. Doing this, we have

-16 * 2² + 300 * 2 + 30

-16 * 4 + 600 + 30

-64 + 630 = 566 ft

Then, we can therefore conclude that the rocket will rise high up to a distance of 566 ft