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AB and CD intersect each other at O and O is the mid-point of both AB and CD. Prove that AC = BD and AC || BD.

User Praemon
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Answer:

Following are the proving to this question:

Explanation:

Please find the graph image in the attachment.

Given O is the mid-point of AB and CD


\to OA=OB \\\\\to OC=OD\\\\In\ \Delta AOD,\Delta BOC\\\\AO=BO\\\\ CO=DO\\\\ \angle AOD= \angle BOC (\text{vertically opposite angles}) \\\\


By \ S.A.S \ congruency \\\\\Delta AOD \cong \Delta BOC \\\\\to AD=BC

AB and CD intersect each other at O and O is the mid-point of both AB and CD. Prove-example-1
User Yesid
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