Question

1. A student weighing 460.0 N climbs a vertical stairway that is 4.5 m high in 32.5 seconds. What is his power output?

2. A worker pushes horizontally on a large crate with a force of 215.0 N and the crate moved 2.6 m. How much work was done?
3. While rearranging a dorm room, a student does 318.0 J of work in moving a desk 2.4 m. What was the magnitude of the applied horizon

Answer 1

1. Power = 63.69 Watts.

2. Workdone = 559 Joules.

3. Force = 132.5 Newton.

Step-by-step explanation:

Given the following data;

1. Force = 460N

Distance = 4.5m

Time = 32.5 seconds.

To find the power;

First of all, we would determine the work done by the student using the formula;

Workdone = force * distance

Workdone = 460 * 4.5

Workdone = 2070 Joules.

Now, we can calculate the power;

Power = workdone/time

Power = 2070/32.5

Power = 63.69 Watts.

2. Force = 215N

Distance = 2.6 m

To find the work done by the worker;

Workdone = 215 * 2.6

Workdone = 559 Joules.

3. Workdone = 318 Joules

Distance = 2.4m

To find the magnitude of force applied;

Force = workdone/distance

Force = 318/2.4

Force = 132.5 Newton.