Question

In the figure given below, AB is a diameter of the circle with center o

0
B
D
If m ZABC - 30 and m ZCAD = 140" what is m ZBAD?
600
700
80
1100
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O

Answer 1

80° is the answer

Explanation:

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Answer 2

∠ BAD = 80°

Explanation:

∠ ACB = 90° ( angle in a semicircle )

∠ CAB = 180° - (90 + 30)° ← sum of angles in Δ ABC

∠ CAB = 180° - 120° = 60°

Then

∠ BAD = ∠ CAD - ∠ CAB = 140° - 60° = 80°