Question

A person whose mass is 80 kg has a surface area on one foot of 0.05 m2. What pressure does the person exert on the ground if standing on both legs?

Answer 1

P=F/A

A=foot1+foot2

A=0.05m2+0.05m2 because it says by two foot

A=0.10m2

>>F=mg=80kg*9.81m/s2=784.8N

P=784.8N/0.10m2

P=7848Pa