Question

A power winch is designed to raise a 4,961 N load 10 meter in 2 minutes. The winch is designed with a 283 mm diameter drum taking up the wire lifting the load. The drum will be connected to a 9 rpm motor through a gearbox. What is the minimum torque (Nm) that the motor shaft coupling should be designed to transmit

Answer 1

T = 438.87 N.m

Step-by-step explanation:

The power required to raise the 4961 N load in 10 meters for 2 minutes is:

`P = (4961*10)/(2*60)\\ \\ P = 413.42 Nm/sec`

P = Torque × W

`413.42 = T * (2 * \pi*9)/(60)`

`413.42 = T *0.942 \\ \\ T = (413.42)/(0.942)`

`T = (413.42)/(0.942)`

T = 438.87 N.m