Question

What volume of Nitrogen measured at s.T.P. Will be produced on heating 33.8g of calcium trioxonitrate

Answer 1

9.2288 L

Step-by-step explanation:

The equation of the reaction is given as;

2 Ca(NO3)2 → 2 CaO + 4 NO2 + O2

From the reaction;

2 mol of Ca(NO3)2 produces 4 mol of NO2

Converting 33.8g to Number of moles;

Number of moles = Mass / Molar mass

Number of moles = 33.8 g / 164.088 g/mol

Number of moles = 0.206 mol

2 = 4

0.206 = x

Solving for x;

x = 0.206 * 4 / 2

x = 0.412 mol

At STP;

1 mol = 22.4 L

0.412 mol = x

Solving for x;

x = 0.412 * 22.4 = 9.2288 L