Question

What is the Electric Field strength at a point if a charge of 0.7 Coulombs experiences a

force (Fe) of 123 Newtons?

Answer 1

Hi there!

Recall the following equation relating electric force to electric field:

`F_E = qE`

`F_E` = Force due to electric field (N)

`q` = Charge of particle (C)

`E` = Electric Field Strength (N/C)

Rearrange to solve for the Electric Field, and solve.

`E = (F_E)/(q) = (123)/(0.7) = \boxed{175.714 (N)/(C)}`