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A bar of gold is 5.0 cm thick, 10.0 cm long and 2.0 cm wide. It has a mass of exactly 193.0 g. What is the density of gold?

2 Answers

13 votes

Answer:

1.93g/cm^3 = density

Explanation:

M = p • v

M = mass

p = density

v = volume

volume = l • w • h

volume = 10.0 cm • 2.0 cm • 5.0 cm

volume = 100 cm^3

193.0g = p • 100cm^3

divide each side by 100cm^3

1.93g/cm^3 = p

User Rdeetz
by
8.3k points
10 votes

Answer:

1.93 g/cm³

Explanation:

You want to know the density of a gold bar 5 cm thick, 10 cm long, and 2 cm wide with a mass of 193.0 g.

Density

Density is the ratio of mass to volume:

ρ = m/V = (193.0 g)/((5 cm)(10 cm)(2 cm)) = 193/100 g/cm³

ρ = 1.93 g/cm³

The density of this gold bar is about 1.93 g/cm³.

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Additional comment

The actual density of gold is about 19.3 g/cm³. For some reason this gold bar has about 1/10 the density of actual gold. Perhaps it is hollow, or mixed with a lighter element.

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User Lee Daniel Crocker
by
8.3k points

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