Question

3. What three numbers are the Pythagorean triple generated by using 4 for x and 1 for y. Remember to use the formulas:

a = x2 - y2, 6 - 2xy, and C = x2 + y2
O 6, 8, and 10
O 5, 11, and 12
O 8, 15, and 17
O 3, 5, and 8

Answer 1

Given:

Consider the three number are given by:

`a=x^2-y^2`

`b=2xy`

`c=x^2+y^2`

To find:

The three numbers are the Pythagorean triple generated by using 4 for x and 1 for y.

Solution:

We have,

`a=x^2-y^2`

`b=2xy`

`c=x^2+y^2`

Substituting 4 for x and 1 for y, we get

`a=4^2-1^2`

`a=16-1`

`a=15`

Similarly,

`b=2(4)(1)`

`b=8`

And,

`c=4^2+1^2`

`c=16+1`

`c=17`

The three three numbers are the Pythagorean triple are 8,15 and 17.

Therefore, the correct option is C.