Question

A 430 kg motorcycle starts from rest and accelerates to a speed of 12 m/s.

Calculate the net work done on the motorcycle.
a. 42 kJ
b. 31 kJ
c. 38 kJ
d. 35 kJ
e. none of these

Answer 1

Vi = 0

Vf = 12 m/s

ΔV = Vf - Vi

ΔV = 12 m/s

Change in kinetic energy

ΔKE = Kf - Ki

ΔKE = 1/2 mv^2 - 0

ΔKE = 1/2 * 430 kg * (12 m/s)^2

ΔKE = 30,960

ΔKE = 30,960 joules

Work = ΔK

Work = 30,960 J