Answer:
They will both blink again at 3:12 pm.
Explanation:
As indicated by the question, the way to solve is to find the Lowest (or Least) Common Multiple of both numbers.
As such:
![\text{List the factors of 12 and 44:}\\12=2*2*3\\44=2*2*11\\\\\text{Take the common factors only once and multiply them by the non-common factors:}\\2*2*3*11=132 \text{ (LCM)}](https://img.qammunity.org/2022/formulas/mathematics/high-school/sj3is79boig5h6qmvlihc0p122k6uz9k9g.png)
Now knowing the LCM is 132, we convert those minutes into hours and minutes:
![(132)/(60)=2(12)/(60) \text{ (2 hours and 12 minutes)}](https://img.qammunity.org/2022/formulas/mathematics/high-school/mibiyiwdu57v0ht4l9km9y921nukw3r6bx.png)
Add this to the original time:
![1:00\text{ pm } + \text{ }2:12 \text{ }= \text{ }3:12\text{ pm}](https://img.qammunity.org/2022/formulas/mathematics/high-school/c7elvwevvu9fr0cbpyr0zd389pelj5x51w.png)