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Please help me i need it right now please

Please help me i need it right now please-example-1
User Vdua
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Given:

The rate of interest on three accounts are 7%, 8%, 9%.

She has twice as much money invested at 8% as she does in 7%.

She has three times as much at 9% as she has at 7%.

Total interest for the year is $150.

To find:

Amount invested on each rate.

Solution:

Let x be the amount invested at 7%. Then,

The amount invested at 8% = 2x

The amount invested at 9% = 3x

Total interest for the year is $150.


x* (7)/(100)+2x* (8)/(100)+3x* (9)/(100)=150

Multiply both sides by 100.


7x+16x+27x=15000


50x=15000

Divide both sides by 50.


x=(15000)/(50)


x=300

The amount invested at 7% is
300.

The amount invested at 8% is


2(300)=600

The amount invested at 9% is


3(300)=900

Thus, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.

User Keyana
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