How many atoms in 98.2 g of He?

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asked Jan 6, 2022 163k views

3 votes

How many atoms in 98.2 g of He?

Chemistry
high-school

Wlk asked

by Wlk

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023x10^23 He atoms. 1 mole Of Helium = Weight of Helium/4Weight of Helium = 1*4 = 4 grams 1 mole of Helium contains 6.023*10²³ (Avogadro number) atoms. MULTIPLY BY 98.2g FOR COMPLETE ANSWER

Adirio answered Jan 10, 2022

by Adirio

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