How many atoms in 98.2 g of He?

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asked Jan 6, 2022 163k views

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Adirio · Answer 1 · 2022-01-10T16:49:35+0000

023x10^23 He atoms. 1 mole Of Helium = Weight of Helium/4Weight of Helium = 1*4 = 4 grams 1 mole of Helium contains 6.023*10²³ (Avogadro number) atoms. MULTIPLY BY 98.2g FOR COMPLETE ANSWER

How many atoms in 98.2 g of He?

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