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Find the equation of the line that is perpendicular to y=1/3x+10 and passes through (3,-4)​

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Answer:

Explanation:

1. perpendicular slope will be the negative of the reciprocal

2. so this will be -3 ( since the reciprocal of 1/3 is 3 and its negative is -3

3. So use the values given for x and y (3,-4)

4. substitute in the given equation using the -3 for the slope instead of 1/3

5. To find a new b we substitute for x and y

5. y = 1/3x + 10

6. -4 = -3 (3) + b

7. -4= -9+ b

8. b = 5

Equation of the line will be y = -3x + 5

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